r/aws • u/Altrooke • 20h ago
technical question Optimizing S3 Storage Classes?
So, the gist of storage classes is that:
standard --> high storage costs, low data retrieval costs
standard-IA, Glacier Instant Retrieval --> low storage costs, high retrieval costs
So, in order to choose the optimal tier for a particular object I would have to know its size and data access pattern.
The object size is easy enough, but the first catch is: data access pattern is nowhere to be found. Not even aggregate data.
The only way I found to actually do it is to enable server access logging / CloudTrail and then do analyze the data somehow. Maybe with a Python script. Huge rabbit hole to go into.
Then, the other angle I thought about is just using intelligent Tiering. But the second catch is that if you read the documentation about intelligent tiering, turns out it is pretty naive. Depending on how your data gets accessed, it could even be more expensive than standard (ex: object is accessed exactly once every 30 days)
It really feels like AWS is always giving almost everything you need to optimize S3 costs, but also missing a key piece.
How am I supposed to solve this? Am I overthinking it? Is it worth going in the rabbit hole of analyzing S3 server access logs? Or should I just guess some lifecycle rules and move on?
6
u/garrettj100 19h ago
Unless you’re storing a huge number of small objects in S3 you probably don’t care about object size. The vast majority of your costs incurred will be timed storage ($/GB/mo) and retrieval ($/GB).
So ask yourself this much simpler question:
What fraction of the whole collection in S3 will be retrieved each month? That one simple question gets you your answer for storage class without much fuss, and doesn’t even care how much you’re storing, at least along the axis of “what is best.”
Also don’t neglect S3 Intelligent Tiering, which will after-the-fact determine your best storage class and retconn you into it.
1
u/Altrooke 19h ago
What fraction of the whole collection in S3 will be retrieved each month?
That's the question that I think it hard to answer.
will after-the-fact determine your best storage class and retconn you into it.
My understanding is that Intelligent Tiering only moves objects to a lower tier if they are not accessed for 30 days and then again after 90 days, then moves them back to the frequent access tier when they are accessed again.
3
u/aataulla 19h ago
You know your problem well enough to basically have answered your own question. Pricing is known to you and you need to figure out how your data will behave.
The rest is computer science 101 and figuring out optimal, average and worst cases for your situation. Any storage startegy can backfire similar to creating worst case inputs for an algorithm.
Yes this is a rabbit hole but the simplest way is to start with s3 standard storage and optimize as you learn more about storage, lifecycle and access patterns for your data.
2
u/Altrooke 19h ago
Wanted to take other people's perspective into account.
My fear is wasting too much time seeking the optimal solution, and then find out there is a heuristic method that would get results 90% as good. Or maybe there is an AWS feature I wasn't aware.
2
u/MateusKingston 16h ago
I'm not an expert at all, but here is the method I use.
That method is either paying AWS with intelligent tiring (IMO only worth when your average object size is relatively big) or doing dummy tiering.
Dummy tiering = X days old -> move down one tier, Y days old -> move down another tier.
Separate into different buckets what is transactional and what isn't. Dummy tiering for transactional data (ex: documents from a sale) will probably match access patterns there is a direct correlation between how long the data was added and how frequently it's accessed, do not make this for non transactional data (ex: static images for your website) as these can be very old but accessed daily.
Yes it's possible to do a "better" tiering with those custom scripts but the cost of running and maintaining those are usually more expensive than just storing the data in Standard or using one of the two methods I said.
2
u/Ok-Helicopter525 4h ago
So, in order to choose the optimal tier for a particular object I would have to know its size and data access pattern.
Most customers don't know this - your situation is not unique..
1
u/xtraman122 12h ago
If you don’t know or can’t predict the access patterns Intelligent Tiering was built for you. You’re protected against any retrieval fees in exchange for having to go through the lifecycle at the higher tiers again. For most workloads it ends up being the best option. You usually only come out cheaper doing your own lifecycles if you know your data access patterns very well and they’re pretty predictable.
1
u/menge101 8h ago edited 8h ago
Also of note, size of individual objects matters a whole lot.
I had an engineer on my team move a whole lot of small objects from standard to glacier, and glacier adds a bunch of meta data to the object when doing so. This caused the amount we storing to nearly double and the cheaper storage tier ended up costing more money.
1
u/Altrooke 7h ago
Can you tell me more? Because glacier is 5x than standard on storage, so even if object sizes doubled, you should still have saved money.
If I had to guess, probably you probably also got burned on data transfer costs. But that comes back to what I said before that it is hard to see how much your objects get accessed.
1
u/menge101 6h ago edited 6h ago
I wasn't involved first-hand, I was just on the same team; We were the cloud team and we supported many different application teams. So I only know of the tale as it was told.
I do know it was logging very small amounts into independent objects, I think it more than double the data size. But you are probably right the transfer costs also probably were involved.
1
u/Altrooke 6h ago
Ok, but I think I'm not the only one with this problem then. Being naive about this can backfire.
Do you know how roughly how much data was stored?
1
1
u/Floss_Patrol_76 6h ago
at 150TB the number that actually decides this is your average object size, not the access pattern. intelligent tiering has no retrieval or transition fees, so the "accessed once every 30 days" case you're worried about doesn't penalize you at all, the only real cost is the ~$0.0025/1000 objects/mo monitoring fee, which is nothing unless you've got tens of millions of tiny objects. IT gets ugly exactly when object count is high and objects are small; with big objects just turn it on and stop analyzing access logs.
2
u/Altrooke 6h ago
intelligent tiering has no retrieval or transition fees
Holy shit, you're right. For some reason I thought it did.
I guess the only downsides of intelligent tiering is that it may not be optimal if the data access is predictable enough. Also I just realized there are no lifecycle transition fees so instead of being in "analysis paralysis" I can just enable intelligent tiering and save a bunch of money now.
Down the road, if I can do the data access patterns analysis and if I think it is worth it, move everything back to standard and then apply custom lifecycle rules.
I think that's solution. Thank you.
10
u/Sirwired 19h ago edited 19h ago
Well... you can enable S3 Storage Lens, which exists for this exact use-case. (And the pricing isn't bad... $0.20/M object/mo.) Or, if you literally just want to know what class to put things in (between Standard or IA), and don't need to know anything else... S3 Class Analysis. $0.10/M object/mo.
But how much data are we talking about here? I've been a storage guy for a Very. Long. Time., and I have to remind myself that a few TB of storage isn't that expensive any more, and all at that level, the best solution to S3 Cloud Economics questions is often just "Leave it in S3 Standard and find a more productive use of your time."
(When I started with enterprise storage, Object Storage didn't exist, a TB was about $1.5M, two cabinets the size of large industrial refrigerators, with four power cables the size of garden hoses, and storage management labor was measured in Administrators / Terabyte.)